document.write( "Question 450357: how much pure acid should be mixed with 5 gallon of a 20% acid solution in orde to get a 50% acid solution \n" ); document.write( "
Algebra.Com's Answer #309790 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! .50x=1+(x-5) \n" ); document.write( ".50x=x-4 \n" ); document.write( "4=x-.5x \n" ); document.write( ".5x=4 \n" ); document.write( "x=4/.5=8 \n" ); document.write( "8-5=3 gals. of pure acid to be mixed with 5 gals. of 20% acid \n" ); document.write( "5x.20+3=4 \n" ); document.write( "8x.5=4 \n" ); document.write( " |