document.write( "Question 450357: how much pure acid should be mixed with 5 gallon of a 20% acid solution in orde to get a 50% acid solution \n" ); document.write( "
Algebra.Com's Answer #309790 by jorel1380(3719)\"\" \"About 
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.50x=1+(x-5)
\n" ); document.write( ".50x=x-4
\n" ); document.write( "4=x-.5x
\n" ); document.write( ".5x=4
\n" ); document.write( "x=4/.5=8
\n" ); document.write( "8-5=3 gals. of pure acid to be mixed with 5 gals. of 20% acid
\n" ); document.write( "5x.20+3=4
\n" ); document.write( "8x.5=4
\n" ); document.write( "
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