document.write( "Question 450357: how much pure acid should be mixed with 5 gallon of a 20% acid solution in orde to get a 50% acid solution \n" ); document.write( "

Algebra.Com's Answer #309784 by mananth(16946) $\"\"$ $\"About$

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------ percent ---------------- quantity
\n" ); document.write( "dilute acid 20----------------5 gallons
\n" ); document.write( "pure acid 100----------------x gallons
\n" ); document.write( "Total 50 ----------------5+x gallons
\n" ); document.write( "
\n" ); document.write( "20*5+100*x=50(5+x)
\n" ); document.write( "100+100 x=250+50x
\n" ); document.write( "100x-50x=250-100
\n" ); document.write( "50x=150
\n" ); document.write( "/50
\n" ); document.write( "x=3 gallons 100 % pure acid
\n" ); document.write( " \n" ); document.write( "

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