document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=450306>Question 450306</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A photograph of a child has a width 2 inches longer than its length. The parents decide they want a larger version. The picture is made bigger by increasing both its length and its width by 2 inches, its area increases by 20 square inches. What are the dimensions of the original picture? How would you set up and solve this equation?  \r<BR>\n" );
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document.write( "I can guess the bigger picture is 5x7 inches. Since 5x7=35 I subtract the 20 square inches and come up with a 3x5 inch picture. (15) I don't know how to set up and solve this. Please help me. SAL </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #309780 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=309780\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> w(w+2)=A<BR>\n" );
document.write( "(w+2)(w+4)=A+20<BR>\n" );
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document.write( "w2+2w=A<BR>\n" );
document.write( "w2+6w+8=A+20<BR>\n" );
document.write( "4w+8=20<BR>\n" );
document.write( "4w=12<BR>\n" );
document.write( "w=3<BR>\n" );
document.write( "The first photograph is 3\" by 5\".  The second photograph is 5\" by 7\".. </SPAN>\n" );
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