document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=450282>Question 450282</A>: <I><SPAN STYLE=\"word-break: break-all;\"> George a race-walker, is on one end of a 6 mile track. John a average walker is on the other end of the track. The two start walking towards each other and meet in 1/2 hour. If George's average speed exceeds John's by 6 mph, find the speed of both walkers. How do I set up and solve the equation?\r<BR>\n" );
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document.write( "This is what I came up with: r+6= rate of George\r<BR>\n" );
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document.write( "1/2r + 1/2(r+6)=6                 John=3 mph<BR>\n" );
document.write( "1/2r + 1/2r + 3=6                 George=9 mph<BR>\n" );
document.write( "r + 3=6<BR>\n" );
document.write( "r+3-3=6-3<BR>\n" );
document.write( "r=3<BR>\n" );
document.write( "3+6=9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #309731 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=309731\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/2x+1/2(x+6)=6<BR>\n" );
document.write( "1/2x+1/2x+3=6<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "John walks 3mph, George walks 9mph<BR>\n" );
document.write( "1/2x3+1/2x9=3/2+9/2=12/2=6.. </SPAN>\n" );
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