document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=46783>Question 46783</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bike leaves @ 8:00 am traveling at 10 mph.  A car leaves, heading in the same direction @ 11:00 am traveling at 50 mph.  How many minutes after 11:00 will the car overpass the bike.  The computer program gives the answer of 45 minutes, but I can't figure out how?  Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #30969 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=30969\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 'y' expresses distance traveled<BR>\n" );
document.write( "y = 10mph + 30 the biker has already traveled 30 miles when the car leaves<BR>\n" );
document.write( "y = 50mph<BR>\n" );
document.write( "Combine:<BR>\n" );
document.write( "10x + 30 = 50x<BR>\n" );
document.write( "30 = 40x<BR>\n" );
document.write( "3/4 = x<BR>\n" );
document.write( "Sixty minutes in an hour. (60)(3/4) = 45 minutes </SPAN>\n" );
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