document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=450099>Question 450099</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hunter wants to make sausage consisting of 50% Pork, 37% Beef, and the rest venison. How much PORK will he need if he uses 65 pounds of venison? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #309660 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=309660\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hunter wants to make sausage consisting of 50% Pork, 37% Beef, and the rest venison. How much PORK will he need if he uses 65 pounds of venison?<BR>\n" );
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document.write( "To add up to 100%, the sausage must therefore be 13% venison. <BR>\n" );
document.write( "Since the sausage is 13% venison, and he used 65 lbs of venison, we can write<BR>\n" );
document.write( "65/t = 0.13 -> t = 65/0.13 = 500 lb, where t = the total amount of sausage<BR>\n" );
document.write( "Therefore, since the sausage is 50% pork, we have<BR>\n" );
document.write( "0.50*500 = 250 lb<BR>\n" );
document.write( "So he used 250 lbs. of pork </SPAN>\n" );
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