document.write( "Question 450055: A team of 5 is to be chosen from 4 men and 5 women to work on a special project.
\n" ); document.write( "i. In how many ways can the team be chosen?
\n" ); document.write( "ii. In how many ways can the team be chosen to include just three women?
\n" ); document.write( "iii. What is the probability that the team includes just 3 women?
\n" ); document.write( "iv. What is the probability that the team includes atleast 3 women?
\n" ); document.write( "v. What is the probability that the team includes more men than women?
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Algebra.Com's Answer #309632 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "Note: as order is not important, these are solved using Combinations:
\n" ); document.write( " nCx = \"n%21%2F%28x%21%28n-x%29%21%29\"
\n" ); document.write( "A team of 5 is to be chosen from 4 men and 5 women to work on a special project
\n" ); document.write( "i. In how many ways can the team be chosen? 9C5 = 126 ways
\n" ); document.write( "ii. In how many ways can the team be chosen to include just three women?
\n" ); document.write( " 5C3*4C2 = 10*6 = 60 ways
\n" ); document.write( "iii. What is the probability that the team includes just 3 women? 60/126
\n" ); document.write( "iv. What is the probability that the team includes at least 3 women?
\n" ); document.write( " P(at least 3 women) = 1 - P(0 women ) -P(1 women ) -P(2 women )
\n" ); document.write( " = 1 - (0 - 5C1*4C4 - 5C2*4C3) / 9C5
\n" ); document.write( "v. What is the probability that the team includes more men than women?
\n" ); document.write( " P(more men than women) = P(4men) + p(3men) = (5C1*4C4+ 5C2*4C3)/9C5\r
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