document.write( "Question 449967: Factor the polynomial:\r
\n" ); document.write( "\n" ); document.write( "1. x^2 - 49.\r
\n" ); document.write( "\n" ); document.write( "2. 2a^4 - 21a^3 + 49a^2\r
\n" ); document.write( "\n" ); document.write( "3. y^3 + 2y^2 - 81y - 162
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Algebra.Com's Answer #309616 by htmentor(1343)\"\" \"About 
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1. x^2 - 49
\n" ); document.write( "This is the difference of two squares: x^2-49 = (x+7)(x-7)
\n" ); document.write( "2. 2a^4 - 21a^3 + 49a^2
\n" ); document.write( "This has a factor of a^2: 2a^4 - 21a^3 + 49a^2 = a^2(2a^2 - 21a + 49)
\n" ); document.write( "The expression inside the parentheses can be further factored as:
\n" ); document.write( "2a^2 - 21a + 49 = (2a-7)(a-7)
\n" ); document.write( "So the factorization is 2a^4 - 21a^3 + 49a^2 = a^2(2a-7)(a-7)
\n" ); document.write( "3. y^3 + 2y^2 - 81y - 162
\n" ); document.write( "By long division, you can confirm that y+2 is one of the factors, with a remainder y^2-81
\n" ); document.write( "This can be further factored: y^2-81 = (y+9)(y-9)
\n" ); document.write( "So the factorization is y^3 + 2y^2 - 81y - 162 = (y+2)(y+9)(y-9)
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