document.write( "Question 449938: You are given one scrapbook page (12 inches by 12 inches). With only this for your material, you must create a container
\n" ); document.write( "that will maximize volume while minimizing the total area.
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Algebra.Com's Answer #309518 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
I think the answer might be to cut 4 x 4 inch squares out of each corner.
\n" ); document.write( "If you then fold the sides up, you have a 4 x 4 x 4 box open on top.
\n" ); document.write( "the volume is \"+4%2A4%2A4+=+64+\" in3
\n" ); document.write( "The area is \"+5%2A4%2A4+=+80+\" in2
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\n" ); document.write( "Call the squares cut out of the corners \"+x%5E2+\"
\n" ); document.write( "The surface area is then \"+A+=+144+-+4x%5E2+\" in2
\n" ); document.write( "The volume is then \"x%2A+%2812+-+2x%29%5E2+\"
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\n" ); document.write( "Suppose I removed 3.99 x 3.99 in2 from each corner
\n" ); document.write( " \"V+=+3.99%2A+%2812+-+2%2A3.99%29%5E2+\"
\n" ); document.write( " \"V+=+3.99%2A+%2812+-+7.98%29%5E2+\"
\n" ); document.write( " \"V+=+3.99%2A+4.02%5E2+\"
\n" ); document.write( "\"+V+=+64.48+\"
\n" ); document.write( "and
\n" ); document.write( "\"+A+=+144+-+4%2A15.92+\"
\n" ); document.write( "\"+A+=+144+-+63.68+\"
\n" ); document.write( "\"+A+=+80.32+\"
\n" ); document.write( "Both volume and area went up.
\n" ); document.write( "Now try \"+x+=+4.01+\"
\n" ); document.write( "If either volume goes down or area goes up,
\n" ); document.write( "my guess is right
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