document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=449527>Question 449527</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for x\r<BR>\n" );
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document.write( "8^(2x)=13^(x+10)\r<BR>\n" );
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document.write( "Write the exact answer using base-10 logarithms. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #309515 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=309515\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve for x <BR>\n" );
document.write( "8^(2x)=13^(x+10) <BR>\n" );
document.write( "Write the exact answer using base-10 logarithms.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "8^(2x)=13^(x+10)<BR>\n" );
document.write( "taking log of both sides<BR>\n" );
document.write( "2xlog8=(x+10)log13<BR>\n" );
document.write( "2xlog8=xlog13+10log13<BR>\n" );
document.write( "2xlog8-xlog13=10log13<BR>\n" );
document.write( "x(2log8-log13)=10log13<BR>\n" );
document.write( "x=10log13/(2log8-log13) </SPAN>\n" );
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