document.write( "Question 5851: I am unable to solve this problem. Kindly help.\r
\n" ); document.write( "\n" ); document.write( "Log10(x+y)/3 = 1/2(log10x + log10y) Now, prove that x/y + y/x = 7
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Algebra.Com's Answer #3095 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
before anyone can help, you need to explain a couple of things:\r
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\n" ); document.write( "\n" ); document.write( "1. is the 10 the base of the log?
\n" ); document.write( "2. the \"/3\" is this contained within the log ie log((x+y)/3) or outside, as in (log(x+y))/3. Your notation does not make it clear.\r
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\n" ); document.write( "\n" ); document.write( "cheers
\n" ); document.write( "Jon.
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