document.write( "Question 46771This question is from textbook
\n" ); document.write( ": The amount of a radioactive tracer remaining after t days is given by A=A0 e^-0.058t, where A0 is the starting amount at the beginning of the time period. How many days will it take for one half of the original amount to decay?
\n" ); document.write( "10 days
\n" ); document.write( "11 days
\n" ); document.write( "12 days
\n" ); document.write( "13 days\r
\n" ); document.write( "\n" ); document.write( "Thanks
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Algebra.Com's Answer #30947 by adamchapman(301)\"\" \"About 
You can put this solution on YOUR website!
\"A=A%5B0%5D+e%5E-0.058t\"
\n" ); document.write( "\"A=A%5B0%5D%2F2\"
\n" ); document.write( "So:
\n" ); document.write( "\"A%5B0%5D%2F2=A%5B0%5D+e%5E-0.058t\"
\n" ); document.write( "Dividing by \"A%5B0%5D\":
\n" ); document.write( "\"1%2F2=e%5E-0.058t\"
\n" ); document.write( "\"ln%280.5%29=-0.058t\"
\n" ); document.write( "\"t=-ln%280.5%29%2F0.058\"
\n" ); document.write( "\"t=11.9508\" days.\r
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\n" ); document.write( "\n" ); document.write( "I hope this helps,
\n" ); document.write( "Adam
\n" ); document.write( "P.S. please visit my website, it may be helpful to you. The address is www.geocities.com/quibowibbler
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