document.write( "Question 449818:  Solve the system using substitution.
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document.write( "y = 2x + 10
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document.write( "x^2 + y = 13 \n" );
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| Algebra.Com's Answer #309397 by mananth(16946)     You can put this solution on YOUR website! y = 2x + 10 \n" ); document.write( "x^2 + y = 13\r \n" ); document.write( "\n" ); document.write( "x^2+(2x+10)=13 \n" ); document.write( "x^2+2x+10-13=0 \n" ); document.write( "x^2+2x-3=0 \n" ); document.write( "x^2-3x+x-3=0 \n" ); document.write( "x(x-3)+1(x-3)=0 \n" ); document.write( "(x-3)(x+1)=0 \n" ); document.write( "x=3,-1 \n" ); document.write( "y=16,8\r \n" ); document.write( "\n" ); document.write( "(3,16) (-1,8) \n" ); document.write( " |