document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=449672>Question 449672</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Cos theta is -0.6 and theta is in quadrant III, find sin (1/2) theta. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #309387 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=309387\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Cos theta is -0.6 and theta is in quadrant III, find sin (1/2) theta.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "We are working with a 6-8-10 or 3-4-5 right triangle in quadrant III where cos and sin are negative.<BR>\n" );
document.write( "Using half-angle formula for sine function,<BR>\n" );
document.write( "sin x/2=-sqrt((1-cos x)/2)<BR>\n" );
document.write( "           =-sqrt((1-3/5)/2)<BR>\n" );
document.write( "           =-sqrt(2/5/2)<BR>\n" );
document.write( "           =-&#8730;.2 (ans) </SPAN>\n" );
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