document.write( "Question 449787: Use the intercepts to graph the equation.
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Algebra.Com's Answer #309379 by jorel1380(3719) $\"\"$ $\"About$

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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc

Equation $\"3+x+%2B+-3+y+=+9\"$ describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is $\"-a%2Fb+=+-3%2F-3\"$ .

X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 9/3 = 3.
Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 9/-3 = -3.
Slope is -3/-3 = 1.
Equation in slope-intercept form: y=1*x+-3.

$\"graph%28+500%2C+500%2C+3-8%2C+3%2B8%2C+-3-8%2C+-3%2B8%2C+1%2Ax%2B-3+%29+\"$ \n" ); document.write( "

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