document.write( "Question 449785: How can I graph the equation and indentify the y-intercept?
\n" ); document.write( "y=1/5x \n" ); document.write( "
Algebra.Com's Answer #309378 by jorel1380(3719)\"\" \"About 
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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"1+x+%2B+5+y+=+0\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+-1%2F5\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 0/1 = 0.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 0/5 = 0.
  • Slope is -1/5 = -0.2.
  • Equation in slope-intercept form: y=-0.2*x+0.
\"graph%28+500%2C+500%2C+0-8%2C+0%2B8%2C+0-8%2C+0%2B8%2C+-0.2%2Ax%2B0+%29+\"\n" ); document.write( "
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