document.write( "Question 449742: y=2x^2,y=x+3 solve using system of equations algebraically. \n" ); document.write( "
Algebra.Com's Answer #309374 by Math_Teacher_37(4)\"\" \"About 
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\"+y+=+2x%5E2\" and \"y+=+x+%2B+3\"\r
\n" ); document.write( "\n" ); document.write( "Since \"+y+=+2x%5E2\" and \"y+=+x+%2B+3\", this means that \"2x%5E2+=+x+%2B+3\".\r
\n" ); document.write( "\n" ); document.write( "Now, you have to solve for x, using the quadratic formula. Begin by moving the terms on the right side of the equation to the left side:\r
\n" ); document.write( "\n" ); document.write( "\"2x%5E2+-+x+-+3+=+0\"\r
\n" ); document.write( "\n" ); document.write( "Now, in the quadratic form, \"ax%5E2+%2B+bx+%2B+c\", a = 2, b = -1, and c = -3. Substitute these values into the quadratic formula, as shown below.\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-sqrt%28b%5E2-4%2Aa%2Ac%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-1%29+%2B-sqrt%28%28-1%29%5E2+-+4%2A2%2A-3%29%29%2F%282%2A2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-sqrt%281+%2B+24%29%29%2F%284%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-sqrt%2825%29%29%2F%284%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+5%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281%2B5%29%2F4\" OR \"x+=+%281-5%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+6%2F4\" OR \"x+=+-4%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+3%2F2\" OR \"x+=+-1\"\r
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\n" ); document.write( "\n" ); document.write( "The solutions are x = -1 OR x = 3/2.\r
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