document.write( "Question 449709: if an object is projected upward with an initial velocity off 64 ft per sec from a height of 336 feet then its height t sec after it is projected is defined by the equation h= -16t^2 + 64 t + 336. how many sec after it is projected will it hit the ground? \n" ); document.write( "
Algebra.Com's Answer #309373 by lwsshak3(11628)\"\" \"About 
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if an object is projected upward with an initial velocity off 64 ft per sec from a height of 336 feet then its height t sec after it is projected is defined by the equation h= -16t^2 + 64 t + 336. how many sec after it is projected will it hit the ground?
\n" ); document.write( "..
\n" ); document.write( "When object hits the ground its height will be=0
\n" ); document.write( "0= -16t^2 + 64 t + 336
\n" ); document.write( "-16t^2 + 64 t + 336=0
\n" ); document.write( "divide by -16
\n" ); document.write( "t^2-4t-21=0
\n" ); document.write( "(t-7)(t+3)=0
\n" ); document.write( "t-7=0
\n" ); document.write( "t=7 seconds
\n" ); document.write( "t+3=0
\n" ); document.write( "t=-3 (reject, t≥0)
\n" ); document.write( "ans:
\n" ); document.write( "object will hit the ground 7 seconds after it is projected.
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