document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=449709>Question 449709</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if an object is projected upward with an initial velocity off 64 ft per sec from a height of 336 feet then its height t sec after it is projected is defined by the equation h= -16t^2 + 64 t + 336.  how many sec after it is projected will it hit the ground? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #309372 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=309372\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0=-16t2+64t+336<BR>\n" );
document.write( "16t2-64t-336=0<BR>\n" );
document.write( "t2-4t-21=0<BR>\n" );
document.write( "(t-7)(t+3)=0<BR>\n" );
document.write( "t=7 or -3<BR>\n" );
document.write( "Throwing out the negative answer, we get the time t to be 7 seconds.. </SPAN>\n" );
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