document.write( "Question 449778: Solve for x.
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document.write( "2 log x - log 2x = .301
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document.write( "And The Answer Can't Be A Dec. \n" );
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Algebra.Com's Answer #309368 by Alan3354(69443) You can put this solution on YOUR website! Solve for x. \n" ); document.write( "2 log x - log 2x = .301 \n" ); document.write( "------------------- \n" ); document.write( " \n" ); document.write( "log(x/2) = .301 \n" ); document.write( "x/2 = 10^0.301 \n" ); document.write( "x = 2*10^0.301 \n" ); document.write( "--------------- \n" ); document.write( "x =~ 3.99972 \n" ); document.write( "If you meant for 0.301 to be the log(2), then it's \n" ); document.write( "x = 4 \n" ); document.write( "Otherwise, the answer is what it is, and saying it can't be something is senseless. \n" ); document.write( " \n" ); document.write( " |