document.write( "Question 449778: Solve for x.
\n" ); document.write( "2 log x - log 2x = .301
\n" ); document.write( "And The Answer Can't Be A Dec.
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Algebra.Com's Answer #309368 by Alan3354(69443)\"\" \"About 
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Solve for x.
\n" ); document.write( "2 log x - log 2x = .301
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\n" ); document.write( "\"log%28x%5E2%29+-+log%282x%29+=+.301\"
\n" ); document.write( "log(x/2) = .301
\n" ); document.write( "x/2 = 10^0.301
\n" ); document.write( "x = 2*10^0.301
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\n" ); document.write( "x =~ 3.99972
\n" ); document.write( "If you meant for 0.301 to be the log(2), then it's
\n" ); document.write( "x = 4
\n" ); document.write( "Otherwise, the answer is what it is, and saying it can't be something is senseless.
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