document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=449518>Question 449518</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi there,\r<BR>\n" );
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document.write( "I've been having some trouble understanding the directions to one of the problems in my worksheet:<BR>\n" );
document.write( "For Problem's 21-40, first transform the equations so that either the x-coefficients or the y-coefficients are opposite. Then solve by the linear combination method.\r<BR>\n" );
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document.write( "I have provided number 21 to use as an example: <BR>\n" );
document.write( "3x+5y=17<BR>\n" );
document.write( "2x+3y=11\r<BR>\n" );
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document.write( "I have tried solving for x by multiplying each equation by the opposite of the x-coefficient. Ex: (2)3x+5y=17<BR>\n" );
document.write( "                   (3)2x+3y=11\r<BR>\n" );
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document.write( "I wasn't sure if what I was doing was correct. Can you clarify? Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #309357 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=309357\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you are on the right track\r<BR>\n" );
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document.write( "they want you to multiply by quantities so that either the x or y coefficients in the two equations will have the same values but opposite signs,<BR>\n" );
document.write( "so they will be eliminated during linear combination (adding the equations)\r<BR>\n" );
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document.write( "just change one of your multiplication quantities to a negative (you won't always have to do this) </SPAN>\n" );
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