document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=448855>Question 448855</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve each system graphically.Be sure to check your solution.If a system has an infinite number of solutions, use set-builder notation to write the solution set. If a system has no solution state this.Can someone help with this problem because I don't understand it?\r<BR>\n" );
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document.write( "b+2a=2,<BR>\n" );
document.write( "a=-3-b </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #309329 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=309329\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> b+2a=2<BR>\n" );
document.write( "a=-3-b<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "Sub for a in the 1st eqn<BR>\n" );
document.write( "b + 2(-3-b) = 2<BR>\n" );
document.write( "b - 6 - 2b = 2<BR>\n" );
document.write( "-b - 6 = 2<BR>\n" );
document.write( "- b = 8<BR>\n" );
document.write( "b = -8<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "a = -3-b = -3 -(-8) = -3 + 8<BR>\n" );
document.write( "a = 5<BR>\n" );
document.write( " </SPAN>\n" );
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