document.write( "Question 449609: 2zy over y2 =14 over y \n" ); document.write( "
Algebra.Com's Answer #309306 by Gogonati(855)\"\" \"About 
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\"2yz%2Fy%5E2=14%2Fy\",reducing the first term we get:\"2z%2Fy=14%2Fy\"=>\"2z=14\"=>\r
\n" ); document.write( "\n" ); document.write( "=>\"z=7\", substituting z=7 we find y=1.
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