document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=449597>Question 449597</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find 3 consecutive multiples of 4 such that twice the sum of the last two numbers decreased by the second number is 4 less than 5 times the first number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #309292 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=309292\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the multiples be 4x, 4(x+1) and 4(x+2)<BR>\n" );
document.write( "2(4(x+1)+(4(x+2))-4(x+1)=5*4x-4<BR>\n" );
document.write( "2(4x+4+4x+8)-4x-4=20x-4<BR>\n" );
document.write( "8x+8+8x+16-4x-4=20x-4<BR>\n" );
document.write( "12x+20=20x-4<BR>\n" );
document.write( "8x=24<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( ".<BR>\n" );
document.write( "12,16 and 20 are the 3 multiples of 4.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );