document.write( "Question 449344: A line passes through the point (1,3) and has a slope of 4. Write an equation for the line.
\n" ); document.write( "Find the equation of the line that is perpendicular to the first line and passes throgh (1,3).
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Algebra.Com's Answer #309237 by ankor@dixie-net.com(22740)\"\" \"About 
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A line passes through the point (1,3) and has a slope of 4. Write an equation for the line.
\n" ); document.write( "Use the point/slope form to find this equation, (y - y1 = m(x - x1)
\n" ); document.write( "Where, in this equation, m=4, x1=1, y1=3
\n" ); document.write( "y - 3 = 4(x - 1)
\n" ); document.write( "y - 3 = 4x - 4
\n" ); document.write( "y = 4x - 4 + 3
\n" ); document.write( "y = 4x - 1, is the equation of this line
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\n" ); document.write( "Find the equation of the line that is perpendicular to the first line and passes through (1,3).
\n" ); document.write( "The slope relationship of perpendicular lines: m1*m2 = -1
\n" ); document.write( "let m1 = 4, find m2
\n" ); document.write( "4*m2 = -1
\n" ); document.write( "Divide both sides by 4
\n" ); document.write( "m2 = \"-1%2F4\", is the slope of the perpendicular line
\n" ); document.write( ":
\n" ); document.write( "Using the point/slope again, find the equation for the perpendicular line
\n" ); document.write( "y - 3 = \"-1%2F4\"(x - 1)
\n" ); document.write( "y - 3 = \"-1%2F4\"x + \"1%2F4\"
\n" ); document.write( "y = \"-1%2F4\"x + \"1%2F4\" + 3
\n" ); document.write( "y = \"-1%2F4\"x + \"1%2F4\" + \"12%2F4\"
\n" ); document.write( "y = \"-1%2F4\"x + \"13%2F4\", is the line perpendicular to y=4x-1 and passes thru point 1, 3
\n" ); document.write( ":
\n" ); document.write( "Graphically
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-5%2C+5%2C+-5%2C+5%2C+4x-1%2C+-.25x%2B3.25%29+\"
\n" ); document.write( "Note that lines intersect at 1, 3
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\n" ); document.write( "How about this; was it understandable to you? Any questions?
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