document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=449536>Question 449536</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The arc length of a sector of a circle is 8&#960; cm. If the circle has a radius 20&#960; cm, what is the measure of the central angle of the sector?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #309235 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=309235\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The arc length of a sector of a circle is 8&#960; cm. If the circle has a radius 20&#960; cm, what is the measure of the central angle of the sector?<BR>\n" );
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document.write( "Circumference of the circle = 2(pi)r = 2(pi)(20pi) = 40pi^2 cm<BR>\n" );
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document.write( "Let measure of centeral angle be \"x\":<BR>\n" );
document.write( "Solve:<BR>\n" );
document.write( "x/20pi = 360/40pi^2<BR>\n" );
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document.write( "x = (20pi)[360/40pi^2]<BR>\n" );
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document.write( "x = 180/pi degrees ~ 57.30 degrees <BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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