document.write( "Question 449482: An airplane takes five hours to travel a distance of 3600 km against the wind. The return trip takes four hours with the wind. What is the rate of the plane in still air, and what is the rate of the wind? Thank you for your help! \n" ); document.write( "
Algebra.Com's Answer #309224 by Alan3354(69443)\"\" \"About 
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An airplane takes five hours to travel a distance of 3600 km against the wind. The return trip takes four hours with the wind. What is the rate of the plane in still air, and what is the rate of the wind?
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\n" ); document.write( "3600/5 = 720 mph
\n" ); document.write( "3600/4 = 900 mph
\n" ); document.write( "The airspeed is the average = (720+900)/2 = 810 mph
\n" ); document.write( "The windspeed is the difference = 900-810 = 90 mph\r
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