document.write( "Question 449407: Write the equation of a circle in standard form if the endpoints of the diameter are (-8,2) and (6,-4). \n" ); document.write( "
Algebra.Com's Answer #309217 by lwsshak3(11628)\"\" \"About 
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Write the equation of a circle in standard form if the endpoints of the diameter are (-8,2) and (6,-4)
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\n" ); document.write( "Use distance formula to calculate length of diameter:
\n" ); document.write( "Diameter=sqrt(x2-x1)^2+(y2-y1)^2
\n" ); document.write( " =sqrt(-8-6)^2+(2-(-4))^2
\n" ); document.write( " =sqrt(-14^2+6^2)
\n" ); document.write( " =sqrt(232)
\n" ); document.write( " Diameter=15.23
\n" ); document.write( " Radius=7.61
\n" ); document.write( " Radius^2=57.91
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\n" ); document.write( "Use midpoint formula to find center of circle:
\n" ); document.write( "(x,y)=(x1+x2)/2,(y1+y2)/2
\n" ); document.write( " =(-8+6)/2,(2-4)/2
\n" ); document.write( " =-2/2,-2/2
\n" ); document.write( "(x,y)=(-1,-1) (center of circle)
\n" ); document.write( "..
\n" ); document.write( "Standard form for equation of circle:(x-h)^2+(y-k)^2=r^2, (h,k)= (x,y) coordinates of center and r= radius
\n" ); document.write( "For equation of given circle:
\n" ); document.write( "(x+1)^2+(y+1)^2=57.91
\n" ); document.write( "see graph of circle below:
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\n" ); document.write( "y=(57.91-(x+1)^2)^.5-1
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