document.write( "Question 449438: solve elimination/addtion method \r
\n" ); document.write( "\n" ); document.write( "2c - 3d = 14
\n" ); document.write( "5c - 6d = 32 \r
\n" ); document.write( "\n" ); document.write( "show steps
\n" ); document.write( "

Algebra.Com's Answer #309214 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
2c-3d=14 .............1
\n" ); document.write( "5c-6d=32 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by-2
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "-4c+6d= -28
\n" ); document.write( "5c-6d=32
\n" ); document.write( "Add the two equations
\n" ); document.write( "c=4
\n" ); document.write( "plug value of c in (1)
\n" ); document.write( "2c-3d=14
\n" ); document.write( "8-3d=14
\n" ); document.write( "-3d=14 -8
\n" ); document.write( "-3d=6
\n" ); document.write( "d=-2
\n" ); document.write( "
\n" ); document.write( "
\n" );