document.write( "Question 449438: solve elimination/addtion method \r
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document.write( "2c - 3d = 14
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document.write( "5c - 6d = 32 \r
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document.write( "show steps \n" );
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Algebra.Com's Answer #309214 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 2c-3d=14 .............1 \n" ); document.write( "5c-6d=32 .............2 \n" ); document.write( "Eliminate y \n" ); document.write( "multiply (1)by-2 \n" ); document.write( "Multiply (2) by 1 \n" ); document.write( "-4c+6d= -28 \n" ); document.write( "5c-6d=32 \n" ); document.write( "Add the two equations \n" ); document.write( "c=4 \n" ); document.write( "plug value of c in (1) \n" ); document.write( "2c-3d=14 \n" ); document.write( "8-3d=14 \n" ); document.write( "-3d=14 -8 \n" ); document.write( "-3d=6 \n" ); document.write( "d=-2 \n" ); document.write( " \n" ); document.write( " |