document.write( "Question 449482: An airplane takes five hours to travel a distance of 3600 km against the wind. The return trip takes four hours with the wind. What is the rate of the plane in still air, and what is the rate of the wind? Thank you for your help! \n" ); document.write( "
Algebra.Com's Answer #309204 by mananth(16946)![]() ![]() You can put this solution on YOUR website! plane speed = x mph \n" ); document.write( "wind speed = y mph\r \n" ); document.write( "\n" ); document.write( "with wind speed = (x+y) \n" ); document.write( "against wind speed = (x-y)\r \n" ); document.write( "\n" ); document.write( "3600/(x+y)=4 \n" ); document.write( "4x+4y=3600 \n" ); document.write( "/4 \n" ); document.write( "x+y=900....................1 \n" ); document.write( " 3600/(x-y)=5 \n" ); document.write( "3600=5x-5y \n" ); document.write( "x-y=720....................2\r \n" ); document.write( "\n" ); document.write( "Add (1) +(2) \n" ); document.write( "2x=1620 \n" ); document.write( "x=810 mph speed of plane \n" ); document.write( "900-810= 90 mph speed of wind \n" ); document.write( " |