document.write( "Question 46637: Can someone help me on this?\r
\n" ); document.write( "\n" ); document.write( " Suppose that the temperature outside is dropping at a constant rate. At noon, the temperature is 70 degrees F and it drops to 58 degrees F at 5:00 P.M. How much did the temperature change each hour?\r
\n" ); document.write( "\n" ); document.write( " Thanks,
\n" ); document.write( " Lyn
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Algebra.Com's Answer #30920 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
70-58 or a drop of 12 degree in 5 hour thus -12/5=-2.4 degrees per hour\r
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