document.write( "Question 449358: On monday roger drove to work in 16 minutes. Tuesday he averaged 11mph more and it took him 4 minutes less. How far does he travel to work?\r
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document.write( "how would you set this problem up? and solve? Thanks! \n" );
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Algebra.Com's Answer #309166 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! On monday roger drove to work in 16 minutes. \n" ); document.write( " Tuesday he averaged 11mph more and it took him 4 minutes less. \n" ); document.write( " How far does he travel to work? \n" ); document.write( "how would you set this problem up? \n" ); document.write( ": \n" ); document.write( "Let s = his speed on Monday \n" ); document.write( "then \n" ); document.write( "(s+11) = his speed on Tuesday and it takes him 16-4 = 12 min \n" ); document.write( ": \n" ); document.write( "Times have to be in hrs \n" ); document.write( ": \n" ); document.write( "Write a distance equation, dist = speed * time \n" ); document.write( ": \n" ); document.write( "Mon dist = Tues dist \n" ); document.write( "s * \n" ); document.write( "multiply both sides by 60 \n" ); document.write( "16s = 12(s+11) \n" ); document.write( "16s = 12s + 132 \n" ); document.write( "16s - 12s = 132 \n" ); document.write( "4s = 132 \n" ); document.write( "s = \n" ); document.write( "s = 33 mph on monday \n" ); document.write( "then \n" ); document.write( "33 + 11 = 44 mph on Tues \n" ); document.write( ": \n" ); document.write( "Find the dist \n" ); document.write( "33 * \n" ); document.write( ": \n" ); document.write( "Check it on Tuesday, should be the same \n" ); document.write( "44 * |