document.write( "Question 449358: On monday roger drove to work in 16 minutes. Tuesday he averaged 11mph more and it took him 4 minutes less. How far does he travel to work?\r
\n" ); document.write( "\n" ); document.write( "how would you set this problem up? and solve? Thanks!
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Algebra.Com's Answer #309166 by ankor@dixie-net.com(22740)\"\" \"About 
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On monday roger drove to work in 16 minutes.
\n" ); document.write( " Tuesday he averaged 11mph more and it took him 4 minutes less.
\n" ); document.write( " How far does he travel to work?
\n" ); document.write( "how would you set this problem up?
\n" ); document.write( ":
\n" ); document.write( "Let s = his speed on Monday
\n" ); document.write( "then
\n" ); document.write( "(s+11) = his speed on Tuesday and it takes him 16-4 = 12 min
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\n" ); document.write( "Times have to be in hrs
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\n" ); document.write( "Write a distance equation, dist = speed * time
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\n" ); document.write( "Mon dist = Tues dist
\n" ); document.write( "s * \"16%2F60\" = (s+11) * \"12%2F60\"
\n" ); document.write( "multiply both sides by 60
\n" ); document.write( "16s = 12(s+11)
\n" ); document.write( "16s = 12s + 132
\n" ); document.write( "16s - 12s = 132
\n" ); document.write( "4s = 132
\n" ); document.write( "s = \"132%2F4\"
\n" ); document.write( "s = 33 mph on monday
\n" ); document.write( "then
\n" ); document.write( "33 + 11 = 44 mph on Tues
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\n" ); document.write( "Find the dist
\n" ); document.write( "33 * \"16%2F60\" = 8.8 miles
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\n" ); document.write( "Check it on Tuesday, should be the same
\n" ); document.write( "44 * \"12%2F60\" = 8.8 mi
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