document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=449406>Question 449406</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My problem says for me to identify and use geometric sequence. Find the 4th term of the geometric whose first term is 8 and whose common ratio is -3.<BR>\n" );
document.write( "a^4=<BR>\n" );
document.write( "I hope some one can help me. I don't even understand what the problem expects. Thank-you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #309157 by </B><A HREF=/tutors/aboutme.mpl?userid=solver15><B>solver15(27)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver15><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver15><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=309157\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ok let start with the geometeric sequence, the formula for this is an = first term multipy by the ratio raise to power of n-1.<BR>\n" );
document.write( "an= a1.r^n-1<BR>\n" );
document.write( "an=4, r=-3, n=4<BR>\n" );
document.write( "A^4 = 8(-3^4-1)<BR>\n" );
document.write( "A^4 = 8(-3^3)<BR>\n" );
document.write( "A^4 = 8(-27)<BR>\n" );
document.write( "A^4 = -216 so your answer for the 4th term is -216<BR>\n" );
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