document.write( "Question 449373: solving exponential functions: Solve for x. \r
\n" ); document.write( "\n" ); document.write( "log 3^x=-2\r
\n" ); document.write( "\n" ); document.write( "This problem actually looks like: log x = -2
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Algebra.Com's Answer #309120 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
This problem actually looks like: log x = -2
\n" ); document.write( " 3
\n" ); document.write( "----
\n" ); document.write( "base = 3
\n" ); document.write( "exponent of log = -2
\n" ); document.write( "result = x
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\n" ); document.write( "Exponential Form:
\n" ); document.write( "x = 3^-2
\n" ); document.write( "---
\n" ); document.write( "x = 1/9
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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