document.write( "Question 449373: solving exponential functions: Solve for x. \r
\n" );
document.write( "\n" );
document.write( "log 3^x=-2\r
\n" );
document.write( "\n" );
document.write( "This problem actually looks like: log x = -2
\n" );
document.write( " 3 \n" );
document.write( "
Algebra.Com's Answer #309120 by stanbon(75887) ![]() You can put this solution on YOUR website! This problem actually looks like: log x = -2 \n" ); document.write( " 3 \n" ); document.write( "---- \n" ); document.write( "base = 3 \n" ); document.write( "exponent of log = -2 \n" ); document.write( "result = x \n" ); document.write( "----------------------------- \n" ); document.write( "Exponential Form: \n" ); document.write( "x = 3^-2 \n" ); document.write( "--- \n" ); document.write( "x = 1/9 \n" ); document.write( "=========================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " |