document.write( "Question 449355: Can you help me use the zero property or factoring to find the solution of (x+2)(2x+7)=-15 ? \n" ); document.write( "
Algebra.Com's Answer #309110 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
Quadratic Equation in Standard Form\r
\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
\n" ); document.write( "\n" ); document.write( "where \"a\" does not equal \"0\".\r
\n" ); document.write( "\n" ); document.write( "Zero Factor Property\r
\n" ); document.write( "\n" ); document.write( "If a product \"ab+=+0\", then \"a+=+0\" or \"b+=+0\". \r
\n" ); document.write( "\n" ); document.write( "\"0\" is our magic number because the \"only\" way a product can become \"0\" is if at least one of its factors is \"0\"\r
\n" ); document.write( "\n" ); document.write( "you need:\r
\n" ); document.write( "\n" ); document.write( "use the zero property or factoring to find the solution of \r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%282x%2B7%29=-15+\"....first set equation = to \"0\" \r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%282x%2B7%29%2B15=0+\"multiply\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2B4x%2B7x%2B14%2B15=0+\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2B11x%2B29=0+\".....since \"2x%5E2%2B11x%2B29=0+\" cannot be factored,. ... you cannot find the solution of \"%28x%2B2%29%282x%2B7%29=-15+\" by using the zero property or factoring\r
\n" ); document.write( "\n" ); document.write( "only way is to use quadratic formula \r
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Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:

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\n" ); document.write( " Starting with the general quadratic
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\n" ); document.write( " \"ax%5E2%2Bbx%2Bc=0\"
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\n" ); document.write( " the general solution using the quadratic equation is:
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\n" ); document.write( " \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"
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\n" ); document.write( " So lets solve \"2%2Ax%5E2%2B11%2Ax%2B29=0\" ( notice \"a=2\", \"b=11\", and \"c=29\")
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\n" ); document.write( " \"x+=+%28-11+%2B-+sqrt%28+%2811%29%5E2-4%2A2%2A29+%29%29%2F%282%2A2%29\" Plug in a=2, b=11, and c=29
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\n" ); document.write( " \"x+=+%28-11+%2B-+sqrt%28+121-4%2A2%2A29+%29%29%2F%282%2A2%29\" Square 11 to get 121
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\n" ); document.write( " \"x+=+%28-11+%2B-+sqrt%28+121%2B-232+%29%29%2F%282%2A2%29\" Multiply \"-4%2A29%2A2\" to get \"-232\"
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\n" ); document.write( " \"x+=+%28-11+%2B-+sqrt%28+-111+%29%29%2F%282%2A2%29\" Combine like terms in the radicand (everything under the square root)
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\n" ); document.write( " \"x+=+%28-11+%2B-+i%2Asqrt%28111%29%29%2F%282%2A2%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
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\n" ); document.write( " \"x+=+%28-11+%2B-+i%2Asqrt%28111%29%29%2F%284%29\" Multiply 2 and 2 to get 4
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\n" ); document.write( " After simplifying, the quadratic has roots of
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\n" ); document.write( " \"x=-11%2F4%2Bsqrt%28111%29%2F4%2Ai\" or \"x=-11%2F4-sqrt%28111%29%2F4%2Ai\"
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\n" ); document.write( "\n" ); document.write( "as you can see, there is \"NO\" real solutions, only imaginary solutions\r
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