document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5894>Question 5894</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm trying to figure out how to plot the graph y=ln(1-x) by shifting the basic graph for y=ln(x). including the equation of the asymptote, and the coordinates of the y-intercept. Can I think of it as y=ln(-x+1)? Then I could reflect the graph across the y axis and shift it up 1? Would that work? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #3091 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=3091\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i wouldn't do anything like that myself..too easy to get confused.\r<BR>\n" );
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document.write( "What i would do is know what y = ln(x) looks like and then use this as a basis to work out the question.\r<BR>\n" );
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document.write( "So, i assume you know what y=ln(x) looks like? no -ve x-values allowed. The curve starts very close to zero for large -ve y-values and comes through (1,0) before curving away as x increases.\r<BR>\n" );
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document.write( "So, y=ln(1-x) is going to be the same shape more or less.\r<BR>\n" );
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document.write( "if x=0, then y=ln(1) --> 0, so the curve passes through the origin.<BR>\n" );
document.write( "if x=1, then y=ln(0) --> asymptote at x=1.\r<BR>\n" );
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document.write( "So now you can draw the curve: basically a mirror image of ln(x) in shape.\r<BR>\n" );
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document.write( "If you want to put a large -ve x-value in, just to check your shape:\r<BR>\n" );
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document.write( "eg if x=-10, then y=ln(11) --> large +ve value: CORRECT.<BR>\n" );
document.write( "eg if x=+10, then y=ln(-9) --> ERROR: CORRECT.\r<BR>\n" );
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document.write( "Can you see how simpler it is to know the basic curve and then just mess with intercepts and asymptotes to get the \"more complicated\" version?\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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