document.write( "Question 449279: how do you solve \"-12%2Fsqrt%2818x%29\"? I have gotten to \"-12sqrt%28+2%2A9%2Ax+%29%2F%2818x%29\" but am unsure of what to do with the numbers under the radicand \n" ); document.write( "
Algebra.Com's Answer #309078 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
\"-12%2Fsqrt%2818x%29\"
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document.write( "Don't start out multiplying by the entire denominator over itself.\r\n" );
document.write( "Instead, first get the prime factorization of 18 as 2*3²\r\n" );
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document.write( "\"-12%2Fsqrt%282%2A3%5E2%2Ax%29\"\r\n" );
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document.write( "To get a perfect square under the radical,\r\n" );
document.write( "we need to multiply what's under there by another 2 and also\r\n" );
document.write( "by another x, so we multiply by \"sqrt%282x%29%2Fsqrt%282x%29\" which is just 1 in value.\r\n" );
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document.write( "\"%28-12%2Fsqrt%282%2A3%5E2%2Ax%29%29%28sqrt%282x%29%2Fsqrt%282x%29%29\"\r\n" );
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document.write( "Multiplying under the radicals in the denominator:\r\n" );
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document.write( "\"%28-12sqrt%282x%29%29%2Fsqrt%282%5E2%2A3%5E2%2Ax%5E2%29\"\r\n" );
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document.write( "Now we will no longer have a radical in the\r\n" );
document.write( "denominator because we can take the square roots\r\n" );
document.write( "of all those squares\r\n" );
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document.write( "\"%28-12sqrt%282x%29%29%2F%282%2A3%2Ax%29\"\r\n" );
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document.write( "\"%28-12sqrt%282x%29%29%2F%286x%29\"\r\n" );
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document.write( "Then the 6 divides into the 12 and we have:\r\n" );
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document.write( "\"%28-2sqrt%282x%29%29%2Fx\"\r\n" );
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document.write( "Edwin
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