document.write( "Question 449247: 3y squared + 14y = 5 How do I compute this? Thanks for your help \n" ); document.write( "
Algebra.Com's Answer #309073 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"3y%5E2+%2B+14y+=+5\"....use quadratic formula to solve for \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"3y%5E2+%2B+14y+-+5+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"....\"a=3\", \"b=14\" and \"c=-5\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=+%28-14+%2B-+sqrt%2814%5E2-4%2A3%2A%28-5%29+%29%29%2F%282%2A3%29+\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=+%28-14+%2B-+sqrt%28196%2B60%29%29%2F6+\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=+%28-14+%2B-+sqrt%28256%29%29%2F6+\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=+%28-14+%2B-+16%29%2F6+\"\r
\n" ); document.write( "\n" ); document.write( "so, solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"y=+%28-14+%2B+16%29%2F6+\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=+2%2F6+\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=+13\"\r
\n" ); document.write( "\n" ); document.write( "or\r
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\n" ); document.write( "\n" ); document.write( "\"y=+%28-14+-+16%29%2F6+\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=+-30%2F6+\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=+-5\"\r
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\n" ); document.write( "\n" ); document.write( "let's see it on a graph:\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C10%2C+-25%2C+10%2C+3x%5E2+%2B+14x+-+5+%29+\"\r
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