document.write( "Question 449150: How do you find the x-intercepts and the vertex of the graph of the function? Could you also graph the vertex if possible, thank you!
\n" ); document.write( "y=x(x+2)
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Algebra.Com's Answer #309053 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
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\n" ); document.write( "Using the vertex form of a parabola, \"y=a%28x-h%29%5E2+%2Bk\" where(h,k) is the vertex
\n" ); document.write( "y=x(x+2) |Putting into vertex form
\n" ); document.write( "y=x^2 + 2x |Completing the square
\n" ); document.write( "y = (x+1)^2 - 1 |Vertex is (-1,-1) and Line of symmetry is x = -1\r
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