document.write( "Question 449192: Find the reference angle for -144 degrees. \r
\n" ); document.write( "\n" ); document.write( "I'm coming up with 504 degrees, but I think I'm missing a step.
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Algebra.Com's Answer #309046 by stanbon(75887)\"\" \"About 
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Find the reference angle for -144 degrees.
\n" ); document.write( "I'm coming up with 504 degrees, but I think I'm missing a step.
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\n" ); document.write( "The reference angle is ALWAYS an acute angle in the 1st Quadrant.
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\n" ); document.write( "504-360 = 144
\n" ); document.write( "180-144 = 36
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\n" ); document.write( "The reference angle is 36 degrees.
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\n" ); document.write( "How to find the reference angle.
\n" ); document.write( "Sketch 504 degrees on a unit circle.
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\n" ); document.write( "You should find the terminal side
\n" ); document.write( "is in the 2nd quadrant at 144 degrees.
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\n" ); document.write( "Draw a vertical line segment from the
\n" ); document.write( "point where the terminal side meets
\n" ); document.write( "the circle down to the x-axis.
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\n" ); document.write( "The acute angle formed by the x-axis
\n" ); document.write( "and the terminal side is the reference
\n" ); document.write( "angle.
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\n" ); document.write( "Note: This procedure will work for finding
\n" ); document.write( "any reference angle.
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\n" ); document.write( "Example: Find reference for -105 degrees.
\n" ); document.write( "1st: Sketch the angle.
\n" ); document.write( "It's in the 3rd quadrant.
\n" ); document.write( "Draw the vertical line up to the x-axis.
\n" ); document.write( "The acute angle formed by the x-axis
\n" ); document.write( "and the terminal side is 180-105 = 75 degrees.
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\n" ); document.write( "Reference of -144.
\n" ); document.write( "-144 is 36 degrees away from the x-axis.
\n" ); document.write( "Reference of -144 is 36 degrees.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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