document.write( "Question 449184: Replacement times for CD players are normally distributed with a mean of 7.1 years and a standard deviation of 1.4 years. \r
\n" ); document.write( "\n" ); document.write( " Find the probability that a randomly selected CD player will have a replacement time that exceeds 10 years.\r
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\n" ); document.write( "\n" ); document.write( "Find the probability that a randomly selected CD player will have a replacement time of between 5 years and 7.1 years.\r
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\n" ); document.write( "\n" ); document.write( "Two percent of all CD players are replaced in less than how many years?
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Algebra.Com's Answer #309040 by stanbon(75887)\"\" \"About 
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Replacement times for CD players are normally distributed with a mean of 7.1 years and a standard deviation of 1.4 years.
\n" ); document.write( "Find the probability that a randomly selected CD player will have a replacement time that exceeds 10 years.
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\n" ); document.write( "z(10) = (10-7.1)/1.4 = 2.0714
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\n" ); document.write( "P(x > 10) = P(z > 2.0714) = 0.01916
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\n" ); document.write( "\n" ); document.write( "Find the probability that a randomly selected CD player will have a replacement time of between 5 years and 7.1 years.
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\n" ); document.write( "z(7.1) = 0
\n" ); document.write( "z(5)= (5-7.1)/1.4 = -1.5
\n" ); document.write( "P(5< x <7.1) = P(-1.5< z <0) = 0.4332
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\n" ); document.write( "\n" ); document.write( "Two percent of all CD players are replaced in less than how many years?
\n" ); document.write( "Find the z-value with a left tail of 2%.
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\n" ); document.write( "invNorm(0.02) = -2.0537
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\n" ); document.write( "Find the corresponding \"year\" value using x = zs+u
\n" ); document.write( "year = -2.0537*1.4+7.1 = 4.22 years
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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