document.write( "Question 449170: Find the gradient and y intercept for the linear realtions and sketch a graph.
\n" ); document.write( "2x+y=6
\n" ); document.write( "Hi can you help with this please, could you also provide a full explanation please
\n" ); document.write( "Cheers!
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Algebra.Com's Answer #309022 by lwsshak3(11628)\"\" \"About 
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Find the gradient and y intercept for the linear realtions and sketch a graph.
\n" ); document.write( "2x+y=6
\n" ); document.write( "..
\n" ); document.write( "What you have here is an equation of a straight line but you should rearrange the terms so it is in standard form as follows:
\n" ); document.write( "y=mx+b, with m=slope or gradient as you call it (∆y/∆x) and b=y-intercept
\n" ); document.write( "for given equation:
\n" ); document.write( "y=-2x+6
\n" ); document.write( "so, slope=-2 and y-intercept=6
\n" ); document.write( "The following graph is a visual check on these parameters. Notice the y-intercept at 6, and the negative slope of -2=-∆y/∆x. Also, notice the x-intercept at 3 which is obtained by setting y=0, then solving for x.\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+-2x%2B6%29+\"
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