document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=448344>Question 448344</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve log 2x+log 10=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #309013 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=309013\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve log 2x+log 10=3<BR>\n" );
document.write( "..<BR>\n" );
document.write( "log 2x+log 10=3<BR>\n" );
document.write( "log(2x*10)=3 (log multiplication rule)<BR>\n" );
document.write( "change to exponential form:(base(10) raised to log of the number(3)=number(2x*10)<BR>\n" );
document.write( "10^3=2x*10<BR>\n" );
document.write( "1000=20x<BR>\n" );
document.write( "x=50<BR>\n" );
document.write( "check: log(2*50)+log (10)=log 100+log 10=3 </SPAN>\n" );
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