document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=449088>Question 449088</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A coffee manufacturer wants to market a new blend of coffee that sells for $3.92 per pound by mixing two coffees, one that sells for $2.75 per pound, and another that sells for $5.00 per pound. What amounts of each coffee should be blended to obtain 100 pounds of the desired mixture? don't know how to write this equation </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #308997 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=308997\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> --------price	----------------quantity							<BR>\n" );
document.write( "coffee I 2.75----------------xlb						<BR>\n" );
document.write( "coffee II	5----------------100-x	lb						<BR>\n" );
document.write( "Total	3.92%	----------------	100				<BR>\n" );
document.write( "2.75x+5(100-x)=	3.92*	100<BR>\n" );
document.write( "2.75x+500-5x=392		<BR>\n" );
document.write( "2.75x-5x=392-500		<BR>\n" );
document.write( "-2.25x=-108							<BR>\n" );
document.write( "/-2.25											<BR>\n" );
document.write( "x=48	lb	$2.75		<BR>\n" );
document.write( "52 lb	$5.00		<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );