document.write( "Question 449120: How many liters of a 50% alcohol solution must be mixed with 90 liters of a 90% solution to get a 80% solution? Answer is 30L and I keep getting REALLY high numbers. \n" ); document.write( "
Algebra.Com's Answer #308992 by mananth(16946)![]() ![]() You can put this solution on YOUR website! ------ percent ---------------- quantity \n" ); document.write( "Alcohol I 90----------------90 liters \n" ); document.write( "Alcohol II 50----------------x liters \n" ); document.write( "Total 80---------------90+x liters \n" ); document.write( " \n" ); document.write( "90*90+50 *x=80(90+x) \n" ); document.write( "8100+50x =7200+80x \n" ); document.write( "50x-80x= 7200-8100 \n" ); document.write( "-30x=-900 \n" ); document.write( "/ -30 \n" ); document.write( "x=30 liters 50 % alcohol II \n" ); document.write( " \n" ); document.write( " |