document.write( "Question 46608: The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm what are the dimensions (length and width) of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "to start i get\r
\n" ); document.write( "\n" ); document.write( "x^2 + (x+1)^2 = 4^2
\n" ); document.write( "x^2 + x^2 + 2x + 1 = 16
\n" ); document.write( "2x^2 + 2x - 15 = 0
\n" ); document.write( "x^2 + x - 7.5 = 0\r
\n" ); document.write( "\n" ); document.write( "This is where I can't go futher and I need to turn it in tonight. \r
\n" ); document.write( "\n" ); document.write( "Any help please and thank you.
\n" ); document.write( "

Algebra.Com's Answer #30890 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
x^2 + x^2 + 2x + 1 = 16
\n" ); document.write( "2x^2 + 2x = 15
\n" ); document.write( "x^2 + x = 7.5
\n" ); document.write( "(x + 1/2)^2 = 30/4 + 1/4 = 31/4
\n" ); document.write( "x + 1/2 = +-\"sqrt%2831%29\"/2
\n" ); document.write( "x = -1/2 +- \"sqrt%2831%29\"/2
\n" ); document.write( "You can not have a negative measurement, so your answer:
\n" ); document.write( "width = -1/2 + \"sqrt%2831%29\"/2
\n" ); document.write( "length = 1/2 + \"sqrt%2831%29\"/2
\n" ); document.write( "
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