document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=46607>Question 46607</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm what are the dimensions (length and width) of the rectangle.\r<BR>\n" );
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document.write( "to start i get\r<BR>\n" );
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document.write( "x^2 + (x+1)^2 = 4^2<BR>\n" );
document.write( "x^2 + x^2 + 2x + 1 = 16<BR>\n" );
document.write( "2x^2 + 2x - 15 = 0<BR>\n" );
document.write( "x^2 + x - 7.5 = 0\r<BR>\n" );
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document.write( "This is where I can't go futher and I need to turn it in tonight. \r<BR>\n" );
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document.write( "Any help please and thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #30886 by </B><A HREF=/tutors/aboutme.mpl?userid=adamchapman><B>adamchapman(301)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=adamchapman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=30886\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have got to: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2+%2B+x+-+7.5+=+0+ ALIGN=MIDDLE  ALT=\"x%5E2+%2B+x+-+7.5+=+0+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now use the quadratic solver <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "where a=1, b=1 and c=-7.5<BR>\n" );
document.write( "So:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%287.5+%2B-+sqrt%28+56.25%2B30+%29%29%2F2+ ALIGN=MIDDLE  ALT=\"x+=+%287.5+%2B-+sqrt%28+56.25%2B30+%29%29%2F2+\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%287.5+%2B-+sqrt%28+86.25+%29%29%2F2+ ALIGN=MIDDLE  ALT=\"x+=+%287.5+%2B-+sqrt%28+86.25+%29%29%2F2+\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%287.5+%2B-+9.287%29%2F2+ ALIGN=MIDDLE  ALT=\"x+=+%287.5+%2B-+9.287%29%2F2+\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "so the two existing solutions are x=8.394 or x=-0.984 (to 3 decimal places)<BR>\n" );
document.write( "I hope this helps,<BR>\n" );
document.write( "Adam.\r<BR>\n" );
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document.write( "P.S. please check out my website, it may be helpful to you:<BR>\n" );
document.write( "http://www.geocities.com/quibowibbler </SPAN>\n" );
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