document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=448954>Question 448954</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using LAW OF SINES   Round to the nearest tenth.\r<BR>\n" );
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document.write( "Find BC: triangle is laying on it's side with the point to the right point(A).<BR>\n" );
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document.write( "B to C= 61 degrees<BR>\n" );
document.write( "C to A= 23 cm<BR>\n" );
document.write( "A to B= 12 degrees </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #308850 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=308850\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using LAW OF SINES   Round to the nearest tenth.\r<BR>\n" );
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document.write( "Find BC: triangle is laying on it's side with the point to the right point(A).<BR>\n" );
document.write( " <BR>\n" );
document.write( "B to C= 61 degrees<BR>\n" );
document.write( "C to A= 23 cm<BR>\n" );
document.write( "A to B= 12 degrees<BR>\n" );
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document.write( "If I interpret this correctly:<BR>\n" );
document.write( "Angle A = 61º<BR>\n" );
document.write( "Angle C = 12º<BR>\n" );
document.write( "--> B = 103º<BR>\n" );
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document.write( "Side b = 23 cm<BR>\n" );
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document.write( "BC is side a, opposite angle A<BR>\n" );
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document.write( "23/sin(103) = a/sin(61)<BR>\n" );
document.write( "a = 23*sin(61)/sin(103)<BR>\n" );
document.write( "a =~ 20.6 cm\r<BR>\n" );
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