document.write( "Question 448619: How do you find the parabola equation for a parabola that's maximum is (2,8) and the start of the parabola is (o,6) ? \n" ); document.write( "
Algebra.Com's Answer #308835 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Using the vertex form of a parabola, \"y=a%28x-h%29%5E2+%2Bk\" where(h,k) is the vertex
\n" ); document.write( "maximum is (2,8) and the start of the parabola is (0,6) ?
\n" ); document.write( "Standard form is \"%28x+-h%29%5E2+=+4p%28y+-k%29\", where the focus is (h,k + p)
\n" ); document.write( " y = a(x-2)^2 +8 |Using point (0,6) to solve for a
\n" ); document.write( " 6 = a*4 + 8
\n" ); document.write( " -2 = 4a
\n" ); document.write( " -1/2 = a
\n" ); document.write( "y = -.5(x-2)^2 +8 OR -2(y-8) = (x-2)^2
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