document.write( "Question 448876: Hello can you please help me write this equation in standard form and identify the center, vertices, co vertices, and foci.
\n" ); document.write( "x^2+10-4y +1= 0
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Algebra.Com's Answer #308833 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Using the vertex form of a parabola, \"y=a%28x-h%29%5E2+%2Bk\" where(h,k) is the vertex
\n" ); document.write( "x^2+10-4y +1= 0
\n" ); document.write( " 4y = x^2 + 11
\n" ); document.write( " y = (1/4)x^2 + 11/4 Vertex (0,11/4)\r
\n" ); document.write( "\n" ); document.write( "Standard form is \"%28x+-h%29%5E2+=+4p%28y+-k%29\", where the focus is (h,k + p)
\n" ); document.write( " 4y -11 = x^2
\n" ); document.write( " x^2 = 4(y-11/4) 4p = 4, p = 1 focus (0,11/4+1) or (0,15/4)
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